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In the S8E2 episode of Futurama, Benderama, The Professor generates an equation to track the number of Benders that will be generated. It was shown on the screen for a few seconds. Can someone explain what this equation was and how it works?

Screenshot of equation

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I was a math minor and a bad one at that, so I didn't get the equation. What I did get was the significance of the copies being 60% size. For their equation it needed to be above 50% of the size. The idea being each generation is larger in mass than the original. If the size were below 50% the following generations would eventually become so small (in total number at each mass size) that we wouldn't have to worry. –  Justin C Jun 24 '11 at 15:28
    
@JustinC Over the weekend I should be able to post a screenshot, would you be willing to flesh out your answer once that's in place? I'd appreciate a breakdown of how the equation... equates or whatever the term is. –  Keen Jun 24 '11 at 15:46

4 Answers 4

up vote 31 down vote accepted

This equation is actually a red herring.

The Professor is discussing the total amount of mass consumed in order to create all of the Benders, which is equivalent to the total mass of all of the Benders themselves if we assume conservation of mass (i.e. mass in = mass out). This is a safe assumption seeing as how the Professor describes the behavior of the duplication device as "reorganizing the raw material".

Now, a divergent series was needed as a plot device to illustrate how the replication of the Benders would eventually consume all matter available. In this respect, the equation was satisfactory in that it is certainly divergent, being that it is a generalized harmonic series (as Zev correctly identifies in a comment). This is easier to see when it is simplified by noting (as OghmaOsiris did in their answer) that the 2n terms cancel each other:

enter image description here

However, this is not the correct divergent series for this situation.

How low can you go?...

First, we will have to ignore the limiting effects of atomic-sized Benders. After a number of generations, the Benders would get so small that, if they were "normal" matter, they would be comprised of a limited number of molecules, too few to create a complete bending unit. However, one scene shows fully-formed yet still atomic-sized Benders manipulating and ingesting molecules, implying that they are formed not from "normal" matter but from "shrunken" matter. In the Futurama universe this is reasonable since The Professor previously referred to the existence (and extravagant cost) of "tiny atoms" in the episode Parasites Lost when Bender asks the Professor about shrinking them:

Bender: Yo, old guy, why do we have to use those tiny micro-droids? Can't you just shrink us?

Farnsworth: Oh, my, no. That would require extremely tiny atoms, and have you priced those lately? I'm not made of money! Leave me alone!

So, assuming "tiny atoms" are involved, we can safely calculate the mass for an infinite number of generations without worrying about having Benders that are fractions of the mass of a normal atom.

A better choice of equation...

Given that:

  1. Each new generation has 2 times as many Benders as the previous generation, and
  2. Each new Bender is a fixed fraction of the mass of the Bender it spawned from

Then the correct equation for the total mass of all the Benders (and thus the matter they have consumed) as the number of generations approaches infinity is this:

enter image description here

Where M0 is the mass of the original Bender and rmass is the ratio between the mass of a Bender copy and the Bender it spawned from. This is a geometric series, and I guess this equation isn't as interesting looking as the other equation they used. Maybe they chose the equation that they could display in a more complex way, or maybe they just made a mistake. Such is science fiction. ;)

Now, does this equation diverge as the premise of the episode requires? Whether or not the equation is convergent is determined by the value of rmass. In the episode, Bender alludes to his first 2 copies as being "60%-scaled replicas of me". Whether you apply this scaling factor to the physical dimensions or to the mass will give very different results.

Scaling the physical dimensions by 60%...

If we compare the heights and widths of successive Benders, it does appear that they are scaled by 60%. Using this screenshot, I made a few rough measurements (shown in red):

enter image description here

The ratio between these measurements came out to be 0.594 for the height and 0.599 for the width. As Erik notes in his answer, scaling each dimension by 0.6 will end up scaling the volume (and thus the mass) by a factor of 0.216. Using this value for rmass gives us a convergent series that asymptotes to a total Bender mass of about 1.76*M0. Not even two Benders worth of mass!

Since many/all of the Bender clones come together at one point in the episode to battle a giant, it's quite clear that there is much more than two Benders worth of clone mass. So, although the physical dimensions do appear to scale by 60% for each new generation, the mass (somehow) does not appear to scale concurrently. Maybe there are Benders replicating themselves more than once, which would invalidate the first assumption I made above.

Scaling the mass by 60%...

If the mass itself scales by 60% between generations, then rmass would be 0.6 and the equation becomes divergent, growing without bound. Yah! That's what we want to see! But, given the discrepancies, it's something of an empty victory, and writing this answer, while fun, was largely "mathsturbatory". Ultimately, you just have to realize that it's science fiction, not science, and the writers won't always get it 100% right.

...It's still one of my all-time favorite shows, though. ;)

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There is nothing fake on the interwebtubes good sir! –  Chad Jun 24 '11 at 19:26
    
huzzah! I knew the 60% size was the key to the divergence, just couldn't handle the equations. –  Justin C Jun 26 '11 at 13:36
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@Justin: Even 50% would be a divergent series; each generation would use exactly the mass of Bender, with no bound on generations. –  user1030 Jun 29 '11 at 14:21
    
I'm glad to see that my taking Calculus II has proven useful –  David Jun 14 '13 at 5:45
    
In a show where a lobster's shell/house can be burnt down underwater by a robot's lit cigar, accurate mathematics are the least of our worries. –  Zibbobz Sep 22 at 18:52

http://pool.theinfosphere.org/images/0/04/Benderama_Maths.png

Still from that episode. Edit: added to the original post

Its basically a summation from 0 to infinity of powers of 2 multiplied by the original amount over the same power of 2 times n+1. Effectively adding a smaller and smaller fraction until the addition to becomes 0.

It could be rewritten as:

M = summation(n = 0 -> infinity): (M_0/n+1), because the 2^n cancels.

You might want to ask math.stackexchange.com if I'm wrong.

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I've added the screenshot to the question itself, so everyone knows what I'm asking about. –  Keen Jun 24 '11 at 16:01
    
Agreed, 2^n cancels in this equation, so it's just a summation of M_0's fractions. I believe it is equal to 2*M_0. –  Jeff Jun 24 '11 at 16:08
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@Jeff: No, the sum of M_0 / (n+1) as n goes from 0 to infinity is infinite (more technically, it is a divergent sum). This is because it's just M_0 times the harmonic series. –  Zev Chonoles Jun 24 '11 at 16:27
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@Jeff: No, the statement that an infinite sum of positive numbers diverges is equivalent to the statement that its partial sums become arbitrarily large. This is because the definition of an infinite sum is the limit of the partial sums. –  Zev Chonoles Jun 24 '11 at 18:21
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Here is an explicit demonstration that the partial sums of the harmonic series become arbitrarily large. –  Zev Chonoles Jun 24 '11 at 18:24

Here's my analysis-- can someone spot a flaw? I'm going to make this the topic of my next Math Mutation podcast. :-)

Rather than kilograms, let's simplify our calculations and measure mass in Bender-masses, or Bs, where the mass of the original Bender is 1B. What is the mass of the two half-Benders he creates?

First we have to define what '60% of the size' means: I think it would be logical to assume we are reducing the measure to .6 times the original in each of the 3 dimensions: length, width, height. Assuming the mass is proportional to the volume, this means that the mass of each mini-Bender is .6*.6*.6 Bs, or .216 times the mass of the original Bender. So, the total mass of the two half-Benders is 2*.216 = .432 Bs. Similarly, the Nth generation of Benders should have mass of (.432)^N Bs, since its mass is .432 times that of the previous generation. And the sum we're dealing with is (1 + .432 + .432^2 + ...).

Good news-- this series converges! The easiest way to see that is to notice that .432 is less than 1/2, so the Nth term is always less than (1/2^N), a well-known convergent series that adds up to 2. (A quick way to prove this is to look at the base-2 number .1111...) So, no matter how many replicas there are, the total mass will be less than 2 Benders, and our planet is safe.

And the writers were just messing with us by flashing that irrelevant equation on the screen.

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Very nice analysis! It's very logical to assume the scaling more likely applies to the dimensions as opposed to the mass, although that unfortunately does away with any chance for a divergent series (which was the main premise of the show). –  gnovice Jun 28 '11 at 3:47

I am a relative math noob, so please excuse me if this is obviously wrong. But it occurs to me that maybe the M in this equation is not meant to be the mass of the resultant Benders but rather the mass of raw material each generation consumes. That would explain why it gets smaller with each generation. If it's an infinite series, the threat of global destruction is of course still there.

Does this make sense?

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I don't recall exactly what the Professor said, but I think he may have mentioned something about having to add an amount of raw material to the machine that is equal in mass to the duplicated objects. If this is true, then the mass of all the Benders will be equal to the mass consumed to create them. Even if the mass consumed to create each Bender were a fraction of their actual mass (which would violate conservation of mass, implying extra mass/energy is being added somehow), then the total mass of consumed matter would simply be the equation I gave multiplied by that fraction. –  gnovice Jun 27 '11 at 14:01
    
@gnovice Your recollection is correct. Mass into machine=mass out of machine –  Keen Jun 27 '11 at 14:55

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