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Jun 16, 2020 at 9:31 history edited CommunityBot
Commonmark migration
Dec 23, 2016 at 15:01 comment added zibadawa timmy @CacheStaheli We can suppose that the Death Star had enough power output to totally disrupt (gravitationally unbind) the entire planet. Gravitational binding energy is equal to $3 G M^2/R$, with $G$ a constant, $M$ the mass, and $R$ the radius of the object. Supposing for simplicity that the density (ratio) $M/R$ is on average the same for the planet and the "city" (the stuff blown up on the planet's surface), the ratio of Planet power/city power is exactly equal to the ratio of their masses. We have to make further guesses about the destruction to get that ratio, but my guess is ~100.
Dec 23, 2016 at 8:19 comment added Matthew Read @CacheStaheli Both of the lines in those quotes are said nearly word-for-word in the movie as well.
Dec 23, 2016 at 1:40 comment added Philip Klöcking Presumably there is also a difference between what seems to be an atmospheric chain reaction (plasma) and the surface being scratched and blowing up the freaking core and therefore the planet from within.
Dec 22, 2016 at 21:42 comment added user40790 @CacheStaheli "Fully Operational"
Dec 22, 2016 at 21:09 vote accept Cache Staheli
Dec 22, 2016 at 21:04 history edited Adamant CC BY-SA 3.0
added 8 characters in body
Dec 22, 2016 at 21:04 comment added Adamant @CacheStaheli - From Rogue One: A Star Wars Story. The novelization.
Dec 22, 2016 at 21:03 comment added Cache Staheli So, comparatively, how strong was Death Star when it destroyed Alderaan? In addition, where did you get those quotes?
Dec 22, 2016 at 21:01 history answered Adamant CC BY-SA 3.0