How wide and deep was the Pau City sinkhole?

Question

In Revenge of the Sith, both General Grievous and Jedi Master Obi-Wan Kenobi visited Pau City. The site was the stage of the conclusive battle of the Clone Wars. But what were the dimensions of the sinkhole the city was built around?

According to Wookieepedia, the diameter (width) of a Core Ship, such as The Unlimited Projection, was 696 meters. In my rough visual comparison of the sinkhole, the width seems to be about 12 times the diameter of the ship, which would result the total measure of around 8,400 meters.

But do we have any official confirmation on this? And what about the depth, which is difficult to measure like this?

Answer 1

The Star Wars: Absolutely Everything You Need to Know factbook states that the city is 11 layers deep. There's also a mention in the Star Wars - Complete Locations book that the docking bays can handle Trade Federation Core Ships (700m x 900m) and in the Revenge of the Sith Novelisation that the landing spaces were

large enough to land a Victory-class Star Destroyer [900m x 200m]

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Assuming the main landing level is around 800 metres high and given that the private landing pad layer used by Grievous appears to be at least 300 meters high, that means that the average layer height is somewhere between 500m-800m.

This places the approximate depth of the main Pau City sinkhole at around 5-8000m, a figure that seems to tally reasonably well with your calculations regarding the sink-hole's width (e.g. around 8-10k)

Answer 2

I think I've finally discovered the right answer for the depth issue. I just watched this documentary, in which Visual Effects Supervisor John Knoll says:

We had a sinkhole that was about six feet diameter and about 12 feet high.

So, according to the model ratio, the depth is roughly twice the diameter. With the earlier determination of 8,400 meter diameter, it would make the Pau City sinkhole 16,800 meters deep!