During the events of Star Trek Beyond (2016), an Abramsverse/Kelvin Timeline film, the crashed USS Franklin is found and salvaged.
Looking at the actual timeline of events, the USS Franklin is reported lost in 2164, while the split of the Prime/Kelvin timelines occurrs in 2233. This means that the USS Franklin has been sitting there on Altamid for almost 70 years before the timelines split, and so the Franklin would be considered lost in the prime timeline as well.
Do we have any information on the fate of the Franklin in the Prime timeline? I'm imagining that while Picard is literally burying Kirk on Veridian III in 2371, the Franklin is still literally gathering dust on Altamid and guarded by an elderly Jaylah, but have there been any official hints that this is or is not the case?
From an out-of-universe perspective, the ship was most likely invented for the film Star Trek Beyond and so wouldn't have gotten screen time on any previous episode or film, but if this is not the case (e.g. "If you squint, you can see 'USS Franklin NX-326' on a manifest of ships docked at Deep Space Nine in 2372...."), then that would be an answer.
- Is the ship still lost, gathering dust on Altamid?
- Do the incidents with the ship and the Swarm happen "off-screen" from the perspective of the Prime timeline? That is, more or less the same things happen, but Kirk may or may not be involved, etc., and/or it might cover some "lost years" content.
- Do the ship and associated characters have a completely different fate? E.g. "According to the 2019 novel Jaylah v. Picard, Prime Krall gives up his experiments on the Swarm and restores the Franklin with Jaylah, and they fly off to become pirates, attacking dozens of dilithium cargo ships and miners over the years and building a criminal empire. Many decades later, they are hunted down and blown up by a young Picard in command of the USS Stargazer."
A fully canonical answer is of course preferred, but if this has only been addressed in material of lower canonicity such as novels, that would be an answer.