We have already established why the design of the Death Star does not require a gravitational field emanating radially from its center (and thanks for all the great answers).

But then, why does it have to be spherical? With a gravitational field running along a preferred direction, would it not make more sense to make it, say, cubical so that every level optimizes the amount of interior space relative to the amount of exterior shell around it?

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    But then how could it be confused for, and possibly ignored as, "a small moon"? I theorize it was designed to be as close to a lunar disguise as could be made.
    – wbogacz
    Oct 3, 2014 at 0:46
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    @wbogacz - It's intended to be invulnerable to everything but another death star. Why would they need the element of surprise at all?
    – Valorum
    Oct 3, 2014 at 9:25
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    "...optimizes the amount of interior space relative to the amount of exterior shell..." means spherical. Since we tend to like rooms to be square and not arcs, though, the practically usable space might be lower in a sphere.
    – Tim S.
    Oct 3, 2014 at 13:36
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    @TimS. For a 150km sphere the fraction of rooms that need to have round walls/ceilings/flooring is negligible. Oct 3, 2014 at 14:18
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    @ThePopMachine I don't think they'd need any curved surfaces, honestly. The volume where the curvature would be highest, at the core, is completely given over to machinery. The shells above that would be sufficiently large that they could be made locally flat without any real issues. Very long hallways and roads would curve downward, but that's not really a negative quality, it's just unusual for us. Oct 4, 2014 at 0:31

6 Answers 6


Not to bring too much reality to canon here or anything... but from the perspective of a military engineer (me -- 6 years 18C):

While a sphere is indeed the shape most optimized to contain the largest volume in the smallest surface area, this is actually the worst possible thing you can do for a defensive structure. The best defensive structures look like triangles (when undermanned), and grow extrusions as resources become available (as in, angular extensions ending in a point). So a defensively optimized Death Star would look more like a giant version of the 1980's rendition of Superman's babyhood spaceship than a ball.

The reason for this is it concentrates defensive fields of fire, observation and clearly defines the line of final protective fire. At the same time this shape forces an approaching enemy into increasingly tight channelized zones within which obstacles, traps and interdiction devices can be placed, and such spaces can even serve as advantaged terrain within which to fight entire self-contained battles against the channelized enemy without threatening any worse than a breach to three extrusions at a time. These extrusions should be internally segregated from anything critical (so extrusions might house perishable storage, storage for dangerous stuff that might burn/explode, non-critical living areas, etc. while the entire extrusion should be only a conceptual "drawbridge" away from isolation from the next inner defensive wall/barrier).

Imagine being a gunner on a ball-shaped Death Star: your field of fire is greater than 180 degrees in three dimensions. Its you against literally more than half the universe. In addition, even at the Death Star's vast size, an enemy could approach quite close and still be below your meaningful horizon. The solution to this is to place defenses on towers, which now exacerbates the situation of marking a field of fire. In real life we try to limit a defender's field of fire to less than 60 degrees in two dimensions (ideally ~30 degrees along the horizon, or buttressed against a wall on one side in the case of a vertical field of observation), and ideally have the defenders shooting where one limit of fire is the wall of the defensive structure itself and the other only slightly angled from it -- this gives them a meaningfully narrow field of observation and vastly increases the chances of them firing in enfilade. The idea with fast moving targets like fighter craft is to have the enemy fly into your shots, not to try and track their course. This is a lot easier if their path of egress is limited by physical barriers instead of having over 180^3 degrees of freedom.

In a fight against small, fast-moving, highly-maneuverable fighters this is optimal -- it deprives them of their speed and agility. In a fight against large cruisers it would probably also be an ideal layout because scoring a critical, large hit would be difficult, as everything important is deeply nestled within the prongs, drastically limiting the opportunity for a meaningful hit on target for a capital ship.

The star-like shape I am describing is actually the way that firebases (well, when a competent engineer is involved -- not always the case), patrol bases (at least when real infantry do it), and even castles and coastal defenses going back hundreds of years have been built. "Round" is a maximally taxing shape from a defensive engineers point of view and an attacker's dream come true.

All that said, I doubt that anybody involved in the production of Star Wars was a infantryman, a military engineer, or had ever taken machine guns 101. To stay in-universe and give a reason, however, requires some pretty creative thinking. Looking at the project from a cost point of view, a sphere might be quite attractive. Looking at it from an energy conservation point of view this may also be the case, as extrusions would massively aggravate the amount of energy required to overcome rotational inertia and actually aim the thing (all that angular momentum stuff you learn about in school -- not that Star Wars seems to pay this much mind elsewhere). In short, anything other than a spherical Death Star would be very costly to aim.

Could cost + maneuver budget + the Emperor's self perception of invincibility* be enough to motivate a spherical design? I don't know -- but from a defensive point of view, it is a critical blunder. But we already knew the design was flawed the first time we saw Luke blow the thing up in an X-Wing!

(* This point being debatable with regard to the Emperor himself, maybe, but certainly stands for the sneering officer that Darth Vader choked out in the briefing room -- and I assume this reflected the majority opinion of fleet officers everywhere. Wouldn't you feel proud to thump your chest if you had a Death Star? Even a round one?)

Anyway, it bears mentioning that the Death Star was not a defensive weapon in concept.

Edit: Adding a few references. There is no online version of the old A-Camp manual (Pappy Jones!), but the above (and a thousand other related) issues are discussed there at length.

Edit: Thoughts on deflectors/shields prompted by a comment from @RonLugge :

I am not a Star Wars canon expert, but I'll make two big assumptions here

  1. That shields cost less than the things they protect (otherwise they would not be cost-effective)
  2. That shields cannot be projected through one another (we never see layered shielding in the movies)

If these two assumptions hold then a star shape is considerably better than a sphere. The outer shield of the Death Star still serves its original purpose and shape. Following the two basic defensive rules that 1) a single layer of defense is no defense, and 2) unmanned obstacles are not obstacles, it is absolutely necessary to physically harden the outer portions of the extended spikes with ablative material*, and most critically, place deflector shields in layers between and among the defensive extensions. This not only makes attacking the Death Star an onion-cutting problem for a large scale fleet attack (the main scenario against which the Death Star's original defenses were supposedly designed), but also provides the Death Star the chance to literally parcel up a large fighter swarm attack into trapped segments which are much easier to deal with.

Considering the immense size of the Death Star and the (almost ludicrous closeness of Star Wars space battles), though, the star-shape would actually be able to physically disrupt formations of capital ships as well. I didn't consider this until I saw an image of a super star destroyer drawn to scale against the Death Star -- at 19km in length, the super star destroyer looked positively tiny.

(* Ablation being drastically improved by the dynamic expanded surface area of any shape other than a sphere -- which is why we don't buy spherical heat-sinks for our computers.)

The main deflector now becomes much more than a simple shield: it can now be used as a tactical element of enemy formation disruption by selectively switching it off to deliberately permit a portion of the attacking formation to enter, and then turning it back on to cut them off from assistance.

Gauging the optimal size of an enemy formation to attack is a tactical issue, but this is the basic idea behind disintegrating tank and infantry defenses, use of double-sided sally ports and the like in ground warfare. A similar technique has been used in real aerial battles, where ground-to-air defenses are deliberately left hidden and unengaged until a selected portion of the enemy formation has crossed them (the fighter screen advancing ahead of a bomber formation, for example) to deliberately isolate a "manageable" formation from the main support body and disrupt the main attack (the bombers) or strip it of its air-to-air support.

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    Death Pyramid just doesn't have the same ring to it. Oct 3, 2014 at 13:26
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    @zxq9 Just a point, but wouldn't the value of your defenses only realy be apparent in traditional ground based combat? The death star is in space = full 3D combat, there is no such thing as terrain to consider in space. A star fort works great when you have to approach on the same x,y coordinates as the walls less so when approaching from above/underneath is just as easy
    – Culyx
    Oct 3, 2014 at 15:39
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    @RobertF We want as spikey a shape as possible, no smooth sides. The optimal placement of weapons is on the tips, innermost corners, and along outer ridges (as you mention) and innermost ridges. This provides a complete wall of fire from and to any direction. Rate of fire, rivetment durability and (especially in the Death Star's case) effective range would dictate the optimal placement of weapons by type (and often not in an intuitive way). What you don't want is a gun sitting on a flat or convex surface or pointing perpendicularly out from a wall.
    – zxq9
    Oct 3, 2014 at 15:43
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    Just wait a minute, there. Are you suggesting that the Death Star had a flawed design?
    – Natural30
    Oct 5, 2014 at 15:45
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    Soo... You're saying they should have made a Death Star instead of a Death Sphere?
    – Stephen
    Oct 5, 2014 at 22:48

I did some quick math here, everything is rounded to the nearest kilometer. The internet says that the 1st Death Star was 160 km across, that means it has a radius of 80 km. Therefore it had a volume of 2,144,661 cubic km and surface area of 80,425 square km. If you wanted to build a cube shaped space station that is 2,144,661 cubic km, then it would have a length of 129 km and a surface area of 99,846 square km. The cube would have an extra 19,421 square km of surface area that has to be protected from vacuum, radiation and attack. That is almost a quarter more than the surface area of the sphere. That means they would also need about 24% more turbolasers to provide the same level of coverage. Keep in mind that the inside walls don't need to be air proof or resistant to lasers, only the outside.

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    I agree. The ideal defensible solution is one with the lowest surface area to volume ratio, and a sphere beats every other 3d shape.
    – Firebat
    Oct 3, 2014 at 5:00
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    @Richard I suggest that the cylinder is better suited to protect against attacks from small fighters (that can get in close enough for horizons to matter), but the sphere shape still wins out if its enemy is large and remains at a distance as nearly half the lasers could target the same point in space.
    – Firebat
    Oct 3, 2014 at 9:53
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    You're not wrong. Depending on the angle of attack, you could be hidden from up to about 60% of the cylinder's weapons compared to precisely 50% of the sphere's.
    – Valorum
    Oct 3, 2014 at 10:03
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    @zxq9 I'd really expect you to elaborate on "Round == Bad in terms of defense" to be taken seriously. Oct 3, 2014 at 13:14
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    @AnthonyGrist I did, in a multi-paragraph answer on this page.
    – zxq9
    Oct 3, 2014 at 13:18

A sphere has an offensive advantage in respect of pointing at a target. Similar to why gun turrets are round, so that they can be rotated on bearings, the sphere allows for rotation in 3D without excessive angular momentum being created and dissipated.

DeathStar weapon dish

It would suffice to have two internal rings at right angles within the DeathStar. Setting one of these in motion would, by conservation of momentum, cause the DeathStar to rotate about that ring's axis but in the opposite direction. When the ring stops rotating, so would the DeathStar (again because of conservation of momentum). Two rings allows the weapon dish to be pointed in any direction.

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    Your last paragraph (which seems to refer to reaction wheels) is not special regarding spheres, but would apply to any shape so long as it had a symmetric distribution of mass (e.g. a cube or tetrahedron of uniform density). As for your first bit, there are no "bearings" in space, anything will spin freely. The only OK-ish quip is that it it potentially minimizes the moment of inertia to avoid the "excessive angular momentum being created and dissipated".
    – Nick T
    Oct 5, 2014 at 17:01

Optimal use of space probably wasn't a key feature in the Death Star's design.

From a tactical stand point there are two practical purposes that the Death Star served: the first was to have massive firepower, and the second was to be (practically) indestructible.

Let's assume that the combination of these features required an extremely large structure but did not require any specific shape. At this point there are a few secondary purposes that the Death Star could have been designed for. The first of these, which incited this question, is optimal use as a military base / administrative hub for the Empire. The tactical advantages granted by this usage are probably minimal and already served by other imperial assets. The second purpose is as a symbol of imperial power, in which case form (e.g. looking intimidating) would most likely trump function.

In short the in-universe reason why the Death Star is spherical is probably the same as the creative reason: because somebody thought it looked imposing and that was more important than practicality.


I've always assumed the entire design of both Death Stars was spherical for one reason only, to provide protection for the reactor... Yes the one that gets blown up on each of them and that is located at the center of it.

That reactor is, clearly, the most important and most critical system of the whole ship and thus it make sense to build the whole structure to be able to protect it. By locating it in the center of a sphere shaped structure yo ensure it's the most protected part.

Leaving aside the plot devices that allow for a single torpedo to destroy which doesn't make any sense but that we have to believe for the shake of the story, a spherical shape is actually a good design decission for protecting a single core source of power equaly.

Note that in a fully finished Death Star, even with shields down and assuming you don't have stupid "route your torpedo through here" exhausts, it is pretty difficult to reach the central core as you would have to go through the outer and inner hull and the whole structure which would demand a big chunk of firepower... And which such a big structure most of it will likely remain active and able to fight back.


Studying Commonalities throughout the Void

The easiest, most natural form for a liquid to take is a sphere. The force of surface tension pulls to form an equilibrium shape which is spherical. Look at the shape a bubble forms into! With a planet there are different forces at work, but the same result.

The designers of the Death Star knew that their moon sized planet destroyer would need to be built into the shape of a moon, That is to say, if the plan was going to be to build it as big as a moon. You might say they had know choice. Then again you might say, that the Dark lord choose to work with nature, as oppose to the Borg, whom, you might say work to "assimilate" nature. Their Cube craft, would bend and round in on its self as its constant upgrades and "assimilations" reaches the size of a small moon. Thats correct, their Cube would manifest structural implosions as its mass succumb to the natural inclination to become round.

Einsteins explanation of relativity explains why bodies in space of great mass form spheres. The fabric of space/time is bent around huge objects. This causes gravity to act uniformly in a sphere. Again, if a rocky planet somehow was made in a cube, there would be tremendous gravitational forces trying to crush it into a sphere!

The Borg Hypercube, larger than their Cube class spacecrafts, are still cubes because they are no where near the size of a moon, planet, or other massive solid object like the Death Star![Examining Commonalities throughout the VOID VERSE.]

As mentioned, any solid object above a certain mass and radius will succumb to the forces of nature and bend in on its self. The self-gravity of the object overcomes the yield strength of even the strongest solid materials of which it is made of. The surface may still be irregular, but overburden pressure causes the rocks deep inside to deform until the planet has a stable spherical shape. For solid bodies, that occurs between 200km and 300km radius, depending on the density and strength of the materials. Dwarf planets, moons and asteroids with radii less than 200km may be more potato-shaped, whereas solid bodies reaching 300km tend to be spherical.

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    You could radically improve this answer by substantially editing out all of the irrelevant info.
    – Valorum
    Oct 3, 2014 at 5:53
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    Did you read the other question, where it was established that the self-gravity of the Death Star is negligible? Oct 3, 2014 at 6:47
  • The Death Star only has a radius of 80km, and it is not a solid object. It is mostly hollow.
    – Red_Shadow
    Oct 3, 2014 at 13:31
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    You know, there are Borg spheres.
    – ajp15243
    Oct 3, 2014 at 14:10

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