It's called the "United Federation of Planets". But can a society located on something other than a planet (e.g. moon, asteroid, space station) become a member?

By "member", I mean that it is directly called such, or it has representatives in the Federation Legislature. Societies that are merely colonies or protectorates don't count (but may later become members).

Planets may not be fully settled, or have factions that aren't part of the Federation. For the purpose of this question, they're still considered to be "on a planet" and therefore don't count.

Canonical sources (TV shows and movies) only, please. Memory Alpha is not canon, and their list of Federation members appears at first glance to be all planets anyway.

  • 1
    Except Earth's Moon?
    – Valorum
    Commented Mar 22, 2022 at 6:35
  • 1
    To be fair to trek canon it is not clear who gets to be a member. For example given Earth surely had colonies on the Moon, Mars, and Alpha Centauri prior to WWIII are all human colonies merely one member? Early trek literature would imply Alpha Centauri is an independent member. But that same literature would also give it a far more exotic backstory. Likewise Vulcan surely had colonies during its aggressive expansion era that stayed unified with Vulcan unlike the lost Romulan tribe. Maquis colonies obviously wanted out. Commented Mar 22, 2022 at 16:38
  • @Valorum: If the TV series or movies call Luna a member, sure.
    – DrSheldon
    Commented Mar 22, 2022 at 23:43

1 Answer 1


Technically Andoria is a moon of a gas giant in ST:Enterprise canon (like Endor is for Star Wars)

enter image description here

(I loathe Enterprise so answering this violated my headcanon)

  • 2
    Having seen STD and ST:Picard makes me yearn for the halcyon days of ST:Enteprise.
    – Valorum
    Commented Mar 22, 2022 at 10:44

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.